Trigonometry Quiz for JEE/NEET preparations

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#5. The minimum value of 3sin^2x + 5cos^2x is

Explanation is given below

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1. Cos2(x+π) = (-cos x )2 = cos2x
2. Sec4x – tan4x = (sec2x + tan2x)(sec2x – tan2x) =(6/13)
3. Cos 1° cos 2° …. Cos 178° cos 179° = cos 1° cos 2° … cos 90°… cos 178° cos 179° = cos 1° cos 2° … 0 ..cos 178° cos 179° = 0
4. Sin4x + cos4 x = (sin2x + cos4x) – 2sin2x cos2x = 1-2sin 2x cos2x which has greatest value 1
5. 3sin2x + 5cos2x = 3(sin2x + cos2x)+2cos2x = 3 + 2 cos2x = 3 because minimum value of cos2x is 0.

Trigonometry Quiz

1. The period of cos2x is
• (2π)2
•  π ()
• 2π
• π/2
2. The value of cos 10 cos 20 …. cos 1780 cos 1790 is equal to
• 0
• -1()
• 1
• 1/2
3. The greatest value of sin4x + cos4x is
• 1()
• 2
• 3
• 1/2
4. The minimum value of 3sin2x + 5cos2x is
• 0()
• 1
• 3
• 5
5. Principal value of tan-1[sin(-π/2 )] = ?
• π/4
• – π/4
• π/2()
• – π/2

Quiz By : Priti Prasanna Samal