# Trigonometry Quiz for JEE/NEET preparations

Trigonometry Quiz is here,

## Results

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### #1. The period of cos^2 x is

### #2. If sec^2x + tan^2x = 6/13 then (sec^4x – tan^4x) is equal to

### #3. The value of cos 1 cos 2 …. cos 178 cos 179 (All in degrees) is equal to

### #4. The greatest value of sin^4x + cos^4x is

### #5. The minimum value of 3sin^2x + 5cos^2x is

Explanation is given below

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## Trigonometry MCQS Explanations

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- Cos
^{2}(x+π) = (-cos x )^{2}= cos^{2}x - Sec
^{4}x – tan^{4}x = (sec^{2}x + tan^{2}x)(sec^{2}x – tan^{2}x) =(6/13) - Cos 1° cos 2° …. Cos 178° cos 179° = cos 1° cos 2° … cos 90°… cos 178° cos 179° = cos 1° cos 2° … 0 ..cos 178° cos 179° = 0
- Sin
^{4}x + cos^{4}x = (sin^{2}x + cos^{4}x) – 2sin^{2}x cos^{2}x = 1-2sin^{ 2}x cos^{2}x which has greatest value 1 - 3sin
^{2}x + 5cos^{2}x = 3(sin^{2}x + cos^{2}x)+2cos^{2}x = 3 + 2 cos^{2}x = 3 because minimum value of cos^{2}x is 0.

## Trigonometry Quiz

- The period of cos
^{2}x is- (2π)
^{2} - π ()
- 2π
- π/2

- (2π)
- The value of cos 1
^{0}cos 2^{0}…. cos 178^{0}cos 179^{0}is equal to- 0
- -1()
- 1
- 1/2

- The greatest value of sin
^{4}x + cos^{4}x is- 1()
- 2
- 3
- 1/2

- The minimum value of 3sin
^{2}x + 5cos^{2}x is- 0()
- 1
- 3
- 5

- Principal value of tan
^{-1}[sin(-π/2 )] = ?- π/4
- – π/4
- π/2()
- – π/2

Quiz By : Priti Prasanna Samal

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